CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A projectile is given an initial velocity ^i+2^j. The Cartesian equation of its path is (g=10ms2)

A
y=2x5x2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9y=12x5x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y=0x5x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5y=x9x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A y=2x5x2
The equation of projectile is given by

y=xtanθ12gx2u2cos2θ

Here,

tanθ=UyUx=21=2

Therefore,

y=2x1210x2(12+22)×11+tanθ=2x1210x2(12+22)×15

y=2x5x2

1432335_1077409_ans_052f7afd32444ca194c5b3601be7da0b.PNG

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Problems
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon