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Question

A projectile is thrown at some angle with the ground. If at a height of 0.4 m from the ground the velocity vector is equal to v=(6^i+2^j) m/s then angle of projection from the ground will be (Take g=10m/s2)

A
300
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B
450
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C
530
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D
600
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Solution

The correct option is D 300
Given,
h=0.4m
g=10m/s2
v=6^i+2^j m/s
The horizontal component of velocity,
vx=6m/s
The vertical component of velocity
vy=2m/s
As, we know that the horizontal component remains constant,
vx=ux=6m/s
Vertical component,
vy2=uy2+2ayh
22=uy22×10×0.4
uy=23m/s
Now, the angle of projecton is, tanθ=uyux
θ=tan1(236)
θ=300
The correct option is A.


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