Question

(A projectile projected at an angle ${30}^{\circ }$ from the horizontal has a range R. If the angle of projection at the same initial velocity be ${60}^{\circ }$, then the range will be

• A. $R$
• B. $2R$
• C. $R/2$
• D. $R^2$

Answer 1

Answer: (A)

$R$

Range of projectile is given by:

$R=\frac{u^2\sin 2\theta }{g}$

$R_1=\frac{u^2\sin 2\theta }{g}$

$R_2=\frac{u^2\sin 2({90}^o-\theta )}{g}=$$\frac{u^2\sin 2\theta }{g}$

$⟹R_1=R_2$

Horizontal range depends upon angle of projection and it is same for complementary angles i.e. $\theta$ and $(90-\theta ).$

For complementary angles of projection horizontal range is same.