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Question

(A projectile projected at an angle $$30^\circ$$ from the horizontal has a range R. If the angle of projection at the same initial velocity be $$60^\circ$$, then the range will be


A
R
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B
2R
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C
R/2
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D
R2
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Solution

The correct option is D $$R$$
Range of projectile is given by:
$$R=\dfrac{u^2\sin2\theta}{g}$$
$$R_1=\dfrac{u^2\sin2\theta}{g}$$
$$R_2=\dfrac{u^2\sin 2(90^o-\theta)}{g}=$$$$\dfrac{u^2\sin2\theta}{g}$$
$$\implies R_1=R_2$$

Horizontal range depends upon angle of projection and it is same for complementary angles i.e. $$\theta$$ and $$(90 - \theta).$$
For complementary angles of projection horizontal range is same.

Physics

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