Question

# (A projectile projected at an angle $$30^\circ$$ from the horizontal has a range R. If the angle of projection at the same initial velocity be $$60^\circ$$, then the range will be

A
R
B
2R
C
R/2
D
R2

Solution

## The correct option is D $$R$$Range of projectile is given by:$$R=\dfrac{u^2\sin2\theta}{g}$$$$R_1=\dfrac{u^2\sin2\theta}{g}$$$$R_2=\dfrac{u^2\sin 2(90^o-\theta)}{g}=$$$$\dfrac{u^2\sin2\theta}{g}$$$$\implies R_1=R_2$$Horizontal range depends upon angle of projection and it is same for complementary angles i.e. $$\theta$$ and $$(90 - \theta).$$For complementary angles of projection horizontal range is same.Physics

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