CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A prokaryotic organism has DNA of length 2250 microns. Considering the distance between adjacent base pairs as 0.34 nm. How many base pairs are present in prokaryotic DNA?

A
4.6 X 106
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4.6 X 109
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6.6 X 106
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6.6 X 109
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 6.6 X 106
DNA stands for deoxyribonucleic acid. It is a polymer of nucleotides. Each nucleotide consists of :
I. Deoxyribose sugar
II. Nitrogenous base
III. Phosphate group

Length of prokaryotic DNA = 2250 microns = 2250 x 106 m
Further, the distance between adjacent pairs= 0.34 nm= 0.34 x 109 m
The number of base pairs = total length of DNA / distance between adjacent base pairs
= 2250 x 106/ 0.34 x 109
= 6.6 x 106

Hence the correct answer is option C.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon