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Question

A proton and an alpha particle are accelerated through the same potential difference. The ratio of their de Broglie wavelengths ( p ) is :


A
1
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B
2
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C
8
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D
18
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Solution

The correct option is C $$\sqrt{8}$$
We know, $$ \lambda = \dfrac{h}{\sqrt{2mqV}} $$

Since protons and $$ \alpha $$ particles are accelerated through same potential .$$ V $$ is same.

$$\dfrac{\lambda_p}{\lambda_\alpha}  =  \dfrac{\sqrt{2(4m)(2q)V}}{\sqrt{2mqV}}  =  \sqrt{8}$$  

Physics

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