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Question

A pulley system is attached to a massless board as shown below. The board pivots only at the pivot point. A 10 kg mass m sits exactly in the middle of the board.

If the angle θ is 30, the minimum force F ( in N) necessary to lift the 10 kg mas is-


Solution

Let, L be the length of the board and let tension in the string is F.
Now balancing the torque,
MgL2=2FL (T=F)
F=Mg4=10×104=25N

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