A quadrilateral ABCD is drawn to circumscribe a circle (see Fig.) . Prove that AB+CD=AD+BC
Let theP,Q,R,Sbe point of contacts for tangent AB,BC,CD,DA respectively from the figure.
We know that the length of two tangents from one point is equal.
By, adding),(1),(2),(3) and(4) , we get
Hence, AB+CD=AD+BC proved.
A quadrilateral ABCD is drawn to circumscribe a circle (see given figure) Prove that AB + CD = AD + BC