Question

# A racing car has a uniform acceleration of $4{\mathrm{ms}}^{-2}$. What distance will it cover in $10\mathrm{s}$ after start?

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Solution

## Step 1: GivenFinal acceleration, $a=4{\mathrm{ms}}^{-2}$Time period, $t=10\mathrm{s}$The car has uniform acceleration. This means that initially, it was in rest. Thus,Initial velocity, $u=0{\mathrm{ms}}^{-1}$Step 2: Formula usedAs per the second equation of motion,$s=ut+\frac{1}{2}a{t}^{2}$, where $s$ is the distance covered.Step 3: Calculate the distance coveredSubstituting the values in the above equation,$\begin{array}{rcl}s& =& 0×10+\frac{1}{2}×4×{10}^{2}\\ \therefore s& =& 200\mathrm{m}\end{array}$Therefore, the car will cover a distance of $200\mathrm{m}$ in $10\mathrm{s}$ after start.

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