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Question

A racing car has a uniform acceleration of 4ms-2. What distance will it cover in 10s after start?


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Solution

Step 1: Given

Final acceleration, a=4ms-2

Time period, t=10s

The car has uniform acceleration. This means that initially, it was in rest. Thus,

Initial velocity, u=0ms-1

Step 2: Formula used

As per the second equation of motion,

s=ut+12at2, where s is the distance covered.

Step 3: Calculate the distance covered

Substituting the values in the above equation,

s=0×10+12×4×102s=200m

Therefore, the car will cover a distance of 200m in 10s after start.


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