A racing motorboat speeds up in a straight line in a take, from rest. Referring to the acceleration-displacement graph for the speeding boat, find its speed when it passes a raft at a distance of 40 m from the starting point.

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Solution

Area of $v - x$ graph $=$ change in velocity
From $x = 0$ to $x = 40$ ,
area of $a - x$ graph $= \frac{1}{2} \times 1 \times 40 = 20$
change in velocity $= 20$
$V$ at $x = 40$ $-$ initial $v e l = 20$
$V$ at $x = 40$ $-$ $O = 20$
$V$ at $x = 40 = 20 m / s$

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A racing motorboat speeds up in a straight line in a take, from rest. Referring to the acceleration-displacement graph for the speeding boat, find its speed when it passes a raft at a distance of 40 m from the starting point.

Area of v−x graph = change in velocityFrom x=0 to x=40,area of a−x graph =12×1×40=20change in velocity =20V at x=40 − initial vel=20V at x=40 − O=20V at x=40=20m/s

Area of $v - x$ graph $=$ change in velocity
From $x = 0$ to $x = 40$ ,
area of $a - x$ graph $= \frac{1}{2} \times 1 \times 40 = 20$
change in velocity $= 20$
$V$ at $x = 40$ $-$ initial $v e l = 20$
$V$ at $x = 40$ $-$ $O = 20$
$V$ at $x = 40 = 20 m / s$