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Question

A radiation of wavelength λ0 is emitted, when an electron jumps from the third to the second orbit of hydrogen atom. For the electron jump from the fourth to the second orbit of hydrogen atom, the wavelength of the emitted radiation will be,

A
1625λ0
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B
2027λ0
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C
2720λ0
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D
2516λ0
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Solution

The correct option is B 2027λ0
We know that,
1λ=R[1n211n22]

1λ32=R[122132]

1λ0=5R36λ0=365R

And, 1λ42=R[122142]=3R16
λ42=163R

λ42λ0=163R365R=2027 λ42=2027λ0

Hence, (B) is the correct answer.
Why this Question?
This question is based on wavelength of emitted radiation.

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