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Question

A radio transmitter is working at frequency 880 kHz and power 10kW. The number of photons emitted per second will be

A
1327×1034
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B
0.075×1034
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C
1.71×1031
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D
13.27×1034
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Solution

The correct option is C 1.71×1031
The energy of photon is given by
E=hν
where h is Plank's constant, h=6.6×1034Js and ν is the frequency of the photon.
E=6.6×1034×880×103
E=5808×1031
E=5.808×1028J
Now, for the n number of photons emitted per second we can write
nE=P ................................(since, power is energy (emitted or absorbed) per second)

n=PE

n=10×1035.808×1028

n=1.721×1031
So, the answer is option (C).

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