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Question

A rail road curve is to be laid out on a circle. What radius should be used if the track is to change direction by 25 in a distance of 40 metres?


Solution

Let AB be the rail road

AOB=25=25×π180=(5π36)c[  1=(π180)c]

We know that

θ=arcradius   AOB=ABOA   5π36=40r   r=40×365π   r=288π meter   r=91.64 meter    [   π=227]

   r = 91.64 meter

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