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Question

A random variable X has probability distribution 

X12345678P(X)0.130.220.120.210.130.080.060.05

If events are E={x is an odd number},F={x is divisible by 3} and G={x is less than 7}, then the value of P(E(FG)) is


Your Answer
A
0.87
Your Answer
B
0.77
Correct Answer
C
0.52
Your Answer
D
0.82

Solution

The correct option is C 0.52
The events are
E={1,3,5,7}
F={3,6}
G={1,2,3,4,5,6}

Now,
FG={3,6}EFG={1,3,5,6,7}
So,
P{E{FG}}=1(0.22+0.21+0.05)=0.52

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