    Question

# A ray of light is coming along the line x=2 from positive direction of y−axis & strikes a concave mirror whose intersection with the XOY plane is a parabola x2=4y, then equation of the reflected ray after the second reflection is

A
y+2=0
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B
y+1=0
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C
x+2=0
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D
None of these
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Solution

## The correct option is B x+2=0Given equation of parabola is x2=4y=4(1)y ∴ Focus (0,1) and the point of intersection of x=2 & parabola x2=4y is (2,1)Now equation of the first reflection is y=1 which is ⊥er to the incident ray hence second reflected ray is parallel to incident ray & passes through the point (−2,1) The equation after second reflection is x=−2 i.e., x+2=0Hence choice (c) is correct answer.  Suggest Corrections  0      Similar questions
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