    Question

# A ray of light is incident on a surface of glass slab at an angle 45∘. If the lateral shift produced per unit thickness is 1√3 m, the angle of refraction produced is

A
tan1(32)
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B
tan1(123)
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C
sin1(123)
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D
tan1(231)
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Solution

## The correct option is B tan−1(1−√23)Given, Angle of incidence, i=45∘ and, Lateral shift(d)Thickness of a glass slab=1√3 Let r be the angle of refraction. And we know that lateral shift (d) is d=t sin (i−r)cos r ⇒ dt=sin(i−r)cos r ⇒dt=sin i cos r−cos i sin rcos r ⇒d=sin i−cos i tan r Substituting the given values we get, 1√3=1√2(1−tan r)⇒ r=tan−1(1−√23) Hence, option (b) is the correct answer. Why this question? This question provides understanding of application of the formula of lateral shift due to a glass slab.  Suggest Corrections  0      Similar questions
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