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Question

A ray of light is incident upon a parallel sided transparent slab of thickness 9 cm at an angle of incidence 60. If the angle of refraction is 30, the lateral displacement of the light ray is :

A
3 cm
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B
3 3 cm
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C
3 cm
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D
23
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Solution

The correct option is A 3 3 cm
Given:t=9cm,i=60,r=30Distancetravelledbylightinsideglassslabd=tcos(r)=9cmcos(30)=63cmLateraldisplacement=|dsinδ|(whereδ=ri)=63sin(3060)=33cm

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