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Question

A ray of light traveling in air strikes the water surface at an angle of $$40^{o}$$. What will be the refractive index of if angle refraction is $$29^{o}$$.


Solution

we have,

Refractive index, $$n=\dfrac{\sin i}{\sin r}$$

$$=\dfrac{\sin 40}{\sin 29}$$

$$\therefore n=1.32$$


Physics
NCERT
Standard XII

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