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Question

A rectangular coil of 100 turns has length 5 cm and width 4 cm. It is placed with its plane parallel to a uniform magnetic field and a current of 2 A is sent through the coil. Find the magnitude of the magnetic field B, if the torque acting on the coil is 0.2 N m1.

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Solution

τ=nia×B

τ=niBa sin 90

0.2=100×2×5×4×104×b

b=0.5 tesla


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