A rectangular hall has a length of $14 m$ & breadth of $12 m .$ How many square tiles with sides of $10 c m$ are needed to cover the floor of the hall?

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Solution

We have,
$10 c m = \frac{10}{100} = 0.1 m$

Area of floor $= 14 \times 12 m^{2}$

So,
Area of tile $= 0.1 \times 0.1 m^{2}$

No. of tiles required $= \frac{(14 \times 12)}{(0.1 \times 0.1)}$
$= 16800 t i l e s$

Hence, this is the answer.

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A rectangular hall has a length of 14m & breadth of 12m. How many square tiles with sides of 10cm are needed to cover the floor of the hall?

We have,10 cm=10100=0.1 mArea of floor =14×12 m2So,Area of tile =0.1×0.1 m2No. of tiles required =(14×12)(0.1×0.1)=16800 tiles Hence, this is the answer.

A rectangular hall has a length of $14 m$ & breadth of $12 m .$ How many square tiles with sides of $10 c m$ are needed to cover the floor of the hall?

We have,
$10 c m = \frac{10}{100} = 0.1 m$

Area of floor $= 14 \times 12 m^{2}$

So,
Area of tile $= 0.1 \times 0.1 m^{2}$

No. of tiles required $= \frac{(14 \times 12)}{(0.1 \times 0.1)}$
$= 16800 t i l e s$

Hence, this is the answer.