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Question

A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r=2Ω. Two resistance of 6Ω and 3Ω are connected as shown in figure. The external force required to keep the connector moving with a constant velocity v = 2m/s is


A

6 N

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B

4 N

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C

2 N

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D

1 N

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Solution

The correct option is C

2 N


Motional emf e=Bvle=2×2×1=4V

This acts as a cell of emf and internal resistance r=2Ω.

This simple circuit can be drawn as follows

Current through the connector i=42+2=1A

magnetic force on connector Fm=Bil=2×1×1=2N


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