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Question

A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r = 2
Ω. Two resistances of 6Ω and 3Ω are connected as shown in figure. The external force required to keep the connector moving with a constant velocity v = 2m/s is 



A
6N
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B
4N
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C
2N
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D
1N
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Solution

The correct option is C 2N

Motional emf e=Bvl e=2× 2× 1=4 V
This acts as a cell of emf E=4V and internal resistance r=2Ω.
This simple circuit can be drwan as follows



Current through the connector i=42+2=1 A
Magnetic force on connector Fm==Bil=2× 1× 1=2 N (Towards left)


Physics

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