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Question

A rectangular wooden block has mass of 4 kg. The length, breadth and height of this wooden block are 50 cm, 25 cm and 10 cm, respectively. Find the pressure on the table top:

(a) When the wooden block is kept with its surface measuring 50 cm×25 cm on the table.

(b) When the wooden block is kept with its surface measuring 25 cm×10 cm on the table.

(Assume: Acceleration due to gravity, g=10ms2) [5 MARKS]

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Solution

Each problem: 2.5 Mark

Given, mass of wooden block, m = 4 kg,
acceleration due to gravity, g=10 ms2
We know, weight of wooden block, W=m×g
W=4×10
W=40 N
Since, weight is a force, so we can say that the force exerted by the wooden block on the table top is 40 N. We will now calculate the pressure in the two cases.

(a) In the first case: Force = 40 N
and, area=50 cm×25 cm
=50100 m×25100 m
=0.5 m×0.25 m
=0.125 m2
Now, Pressure=ForceArea
=400.125
=320 Nm2
Thus, the pressure exerted by the wooden block on table top when kept on its face measuring 50 cm×25 cm is 320 Nm2 or 320 pascals
(b) In the second case: Force = 40 N
And, Area=25 cm×10 cm
=25100 m×10100 m
=0.25 m×0.1 m
=0.025 m2
Now, Pressure=ForceArea
=400.025
=1600 Nm2
Thus, the pressure exerted by the wooden block on table top when kept on its face measuring 25 cm×10 cm is 1600 Nm2 or 1600 pascals.

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