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Question

A refrigerator whose coefficient of performance is 5, extracts heat from the cooling compartment at the rate of 250 J/cycle. Find the amount of heat discharged per cycle to the room.

A
50 J
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B
250 J
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C
300 J
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D
200 J
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Solution

The correct option is C 300 J
Coefficient of performance of refrigerator is, β=5; Q2=250 J/cycle
where Q2 is the heat extracted per cycle by the refrigerator.
Q1= heat rejected to the source by refrigerator, i.e amount of heat discharged to room.
β=Q2W
Or, 5=Q2W
W=2505=50 J/cycle
from energy conservation on refrigerator,
Q2+W=Q1
Q1=(250+50) J=300 J

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