Byju's Answer

Standard XII

Physics

2nd Law of Thermodynamics

A refrigerato...

Question

A refrigerator works between $3^{o} C$ and $40^{o} C$ . To keep the temperature of the refrigerator constant, 600 cal of heat are to be removed every second. The power required is:

33.78

watt

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337.8

watt

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7.77

watt

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10.77

watt

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Solution

The correct option is A $337.8$ watt
COP of a refrigerator is given by
$C O P = \frac{Q_{c}}{W} = \frac{T_{c}}{T_{h} - T_{c}}$
$W = Q_{c} \frac{T_{h} - T_{c}}{T_{c}} = 600 \times \frac{40 - 3}{3 + 273} = 337.8 w a t t$
Option B.

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A refrigerator works between 3oC and 40oC. To keep the temperature of the refrigerator constant, 600 cal of heat are to be removed every second. The power required is:

The correct option is A 337.8 wattCOP of a refrigerator is given byCOP=QcW=TcTh−TcW=QcTh−TcTc=600×40−33+273=337.8 wattOption B.

A refrigerator works between $3^{o} C$ and $40^{o} C$ . To keep the temperature of the refrigerator constant, 600 cal of heat are to be removed every second. The power required is:

The correct option is A $337.8$ watt
COP of a refrigerator is given by
$C O P = \frac{Q_{c}}{W} = \frac{T_{c}}{T_{h} - T_{c}}$
$W = Q_{c} \frac{T_{h} - T_{c}}{T_{c}} = 600 \times \frac{40 - 3}{3 + 273} = 337.8 w a t t$
Option B.