Question

A resistance of $10\Omega$ and a inductance of $100mH$ are connected in series through an alternating voltage source $V=100\cos \omega t$. Fond out phase difference between current and voltage for the circuit.

Answer 1

Given:
$R=10\Omega$ and Inductance (L)$=100mH$
Voltage source $==100\cos \left(100t\right)$
$V=V_0\cos \omega t;\{V_0=100V;\omega =100rad/s$
$\therefore \tan \varphi =\frac{X_L}{R}=\frac{\omega L}{R}=\frac{100\times 100\times {10}^{-3}}{10}$
$\tan \varphi =1\Rightarrow \varphi =\frac{\pi }{4}={45}^o$