Question

# A resistance 'R' draws power 'P' when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes 'Z', the power drawn will be

A
P(RZ)
B
P
C
P(RZ)2
D
PRZ

Solution

## The correct option is B $$P\left (\frac {R}{Z}\right )^2$$Power $$P = i_{rms} ^2 R=( \frac{V_{rms}}{R})^2R$$Power  when inductor is put in series with R: $$P' = ( \frac{V_{rms}}{Z})^2R$$$$\frac{P'}{P} =\frac{ \frac{R}{Z^2}}{\frac{R}{R^2}}=(\frac{R}{Z})^2$$$$P' = P (\frac{R}{Z})^2$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More