A resistor and an inductor are connected to an AC supply of 120V and 50Hz. The current in the circuit is 3A. If the power consumed in the circuit is 108W, then the resistance in the circuit is
A
12Ω
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B
40Ω
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C
√(52×28)Ω
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D
360Ω
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Solution
The correct option is A12Ω
Given that P=108W We know that P=I2rmsR⇒108=32×R⇒R=12Ω