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Question

A resistor has a resistance of 176 ohms . How many of these resistors should be connected in parallel so that their combination draws a current of 5 amperes from a 220volt supply line ?

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Solution

For Resistors in Parallel,
1/R(total) = 1/R₁ + 1/R₂ + 1/Rₓ
From Ohm's Law
V = IR
220 = (5)R
R = 44 Ω
Therefore
1/44 = No. of 176Ω Resistors * 1/176
Let no. of 176Ω Resistors be x
Then 1/44 = x/176
x = 4
Therefore, 4 resistors of 176Ω ( in parallel) are required to carry 5 A on a 220 V line

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