Question

# A resistor of $$6 k\Omega$$ with tolerance $$10\%$$ and another of $$4k\Omega$$ with tolerance $$10\%$$ are connected in series.The tolerance of combination is about

A
5%
B
10%
C
12%
D
15%

Solution

## The correct option is B $$10\%$$In series combination,$$R=R_1+R_2=6+4=10 k\Omega$$Error in combination$$\Delta R=\Delta R_1+\Delta R_2$$$$\dfrac{10}{100}\times 6+\dfrac{10}{100}\times 4$$$$=0.6+0.4=1$$$$\therefore \dfrac{\Delta R}{R}=\dfrac{1}{10}=10\%$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More