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Byju's Answer
Standard XII
Physics
AC Applied to a Resistor
A resistor of...
Question
A resistor of resistance
100
Ω
is connected to an AC source
ϵ
=
(
12
V
)
s
i
n
(
250
π
s
−
1
)
t
.
Find the power consumed by the bulb.
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Solution
Supply voltage
E
=
12
sin
(
250
t
)
Peak voltage
V
o
=
12
volts
Peak current
I
o
=
V
o
R
=
12
100
=
0.12
Ω
Power consumed
P
=
V
o
I
o
R
=
12
×
0.12
100
=
0.0144
watt
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