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Question

A retarding force is applied to stop a train. The train stops after 80 m. If the speed is doubled, then the distance travelled when same retarding force is applied is 


A
The same
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B
Doubled
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C
Halved
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D
Four times
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Solution

The correct option is C Four times
The stopping distance is given as , $$s=\dfrac{v^2}{2a}$$. 

So stopping distance becomes four times if the initial velocity is doubled.

Physics

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