A retarding force is applied to stop a train. The train stops after 80 m. If the speed is doubled, then the distance travelled when same retarding force is applied is

The same

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Doubled

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Halved

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Four times

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Solution

The correct option is C Four times
The stopping distance is given as , $s = \frac{v^{2}}{2 a}$ .

So stopping distance becomes four times if the initial velocity is doubled.

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A retarding force is applied to stop a train. The train stops after 80 m. If the speed is doubled, then the distance travelled when same retarding force is applied is

The correct option is C Four timesThe stopping distance is given as , s=v22a. So stopping distance becomes four times if the initial velocity is doubled.

The correct option is C Four times
The stopping distance is given as , $s = \frac{v^{2}}{2 a}$ .

So stopping distance becomes four times if the initial velocity is doubled.