For cone, h = 3.6 cm, r = 1.6 cm
Volume of the given cone = 1/3 x Π 2 h = (1/3 x 22/7 x 1.6 x .16 x 3.6) cm2
Radius of the second cone = 1.2 cm. Let its height be h1</sup> then,
Volume of the second cone = 1/3 x Π r2 h = 1/3 x 22/7 x 1.2 x h1
it is melted and recasted so , the volume of the cones would be equal, therefore
1/3 x 22/7 x 1.2 x h1 = 1/3 x 22/7 x 1.6 x .16 x 3.6
h1 = (1.6 x 1.6 x 1.6) / (1.2 x 1.2) = 6.4
Hence the height of the second cone is 6.4 cm