Question

# A ring of radius $$0.5$$ mass $$10 kg$$ is rotating about its diameter with angular velocity of $$20\, rad\, s^{-1}$$. Its kinetic energy is :

A
10J
B
100J
C
500J
D
250J

Solution

## The correct option is D $$250 \,J$$Moment of inertia of a ring about its diameter $$I = \dfrac {1}{2} mr^2$$and kinetic energy is given by$$E_K = \dfrac {1}{2} I \omega^2$$$$E_k = \dfrac {1}{4} mr^2 \omega^2$$$$= \dfrac {1}{4} \times 10 \times (0.5)^2 \times (20)^2$$$$= 250\, J$$Physics

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