CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A rocket is launched normal to the surface of the Earth , away from the sun,along the line joining the sun and the Earth. The Sun is 3×10^5 times heavier than the earth and is at a dis†an ce 2.5×10^{4 }times larger than the radius of the Earth.The escape velocity from Earth's gravitational field is V_e =11.2 km s^{-1}. The minimum initial velocity(V_s) required for the rocket to be able to leave the Sun-Earth system is closest to (Ignore the rotation and revolution of the earth and the presence of any other planet.)

Open in App
Solution

99996115787-0-0

flag
Suggest Corrections
thumbs-up
0
mid-banner-image
mid-banner-image
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Select...
similar_icon
Related Videos
thumbnail
lock
Escape Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
Select...