Question

# A's work efficiency is three times than B's and so A is able to finish a job in 60 days less than B. If they work together, they can do this job in ___ days. [Enter your answer in decimals]

Solution

## Time taken by A : Time taken by B = 1 : 3 That is if A takes 1 day to do the work , B will take 3 days. Let the number of days taken by A  be x. Hence B will take x+60 days                                 A's work                                   B's work                                      1                                              3                                    x                                         x+60  ∴3x=x+60  ⇒2x=60 ⇒x=30 Hence, if A takes 30 days to finish the work , then B will take x+60 = 90 days. A's one day of work = 130 B's one day of work = 190 Amount of work done by them in one day if they work together is; 130+190=3+190=490 Hence, together they will complete in the 904 days, which is, 22.5 days. Mathematics

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