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Question

# A sample of a gas at STP contains 3.01×1023 molecules and has a mass of 20.0 grams. This gas would :

A
have a molar mass of 20.0 g/mol and occupy 11.2 liters
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B
occupy 22.4 liters and have a molar mass of 30.0 g/mol
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C
occupy 22.4 liters and have a molar mass of 20.0 g/mol
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D
have a molar mass of 40.0 g/mol and occupy 33.6 liters
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E
have a molar mass of 40.0 g/mol and occupy 11.2 liters
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Solution

## The correct option is E have a molar mass of 40.0 g/mol and occupy 11.2 liters1 mol = 6.022×10233.01×1023=3.01×10236.022×1023=0.5molesHence, as per given, 0.5 moles of gas has mass = 20 grams. So, 1 mol of gas has mass =2×20=40 grams.Hence, we can say that this gas has molar mass = 40 gram/mole. 1 mole gas has 22.4 L volume at STP, hence, 0.5 moles of this gas 11.2 L volume.

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