A sample of O-2-gas is collected over water at 23-C-at a barometric pressure of 751 mm Hg -vapour-pressure of water at 23-C-is 21 mm Hg-The-partial pressure of O-2-gas in the sample collected is - - - - - - -21 mm Hg-751 mm Hg-0-96 atm-1-02 atm-

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Standard XII

Chemistry

Dalton's Law of Partial Pressures

A sample of O...

Question

A sample of $O_{2}$ gas is collected over water at $23^{\circ}$ C at a barometric pressure of 751 mm Hg (vapour pressure of water at $23^{\circ}$ C is 21 mm Hg). The partial pressure of $O_{2}$ gas in the sample collected is ......

21 mm Hg

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751 mm Hg

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0.96 atm

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1.02 atm

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Solution

The correct option is C
0.96 atm

Pressure of $O_{2}$ (dry) = 751 - 21 = 730 mm Hg = $\frac{730}{760}$ = 0.96 atm

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$50 c m^{3}$ of hydrogen is collected over water at $17^{\circ} C$ and 750 mm Hg pressure. Calculate the volume of dry gas at S.T.P. The water vapour pressure at $17^{\circ} C$ is 14 mm Hg.

A sample of $O_{2}$ gas is collected over water at $23^{\circ}$ C at a barometric pressure of 751 mm Hg (vapour pressure of water at $23^{\circ}$ C is 21 mm Hg). The partial pressure of $O_{2}$ gas in the sample collected is ......

A sample of $O_{2}$ gas is collected over water at 23 $^{\circ}$ C at a barometric pressure of 751 mm Hg (vapour pressure of water at 23 $^{\circ}$ C is 21 mm Hg). The partial pressure of $O_{2}$ gas in the sample collected is____.

Q. A sample of

O_{2}

gas is collected over water at

23^{o} C

at a barometric pressure of

751 m m

Hg (vapour pressure of water at

23^{o} C

21 m m

Hg). The partial pressure of

O_{2}

gas in the sample collected is:

O_{2}

is collected over water a t 20C.The pressure inside shown by the gas is 750 mm Hg. What is the pressure due to

O_{2}

it vapour pressure of

H_{2}

O is 18 mm at 20'C?

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A sample of O2 gas is collected over water at 23∘ C at a barometric pressure of 751 mm Hg (vapour pressure of water at 23∘ C is 21 mm Hg). The partial pressure of O2 gas in the sample collected is ......

The correct option is C 0.96 atm Pressure of O2(dry) = 751 - 21 = 730 mm Hg = 730760 = 0.96 atm

A sample of $O_{2}$ gas is collected over water at $23^{\circ}$ C at a barometric pressure of 751 mm Hg (vapour pressure of water at $23^{\circ}$ C is 21 mm Hg). The partial pressure of $O_{2}$ gas in the sample collected is ......

The correct option is C
0.96 atm

Pressure of $O_{2}$ (dry) = 751 - 21 = 730 mm Hg = $\frac{730}{760}$ = 0.96 atm