Question

# A satellite is moving in a circular orbit around earth with a speed $$V$$, If its mass is m, then its total energy will be.

A
34mv2
B
mv2
C
12mv2
D
12mv2

Solution

## The correct option is C $$-\dfrac {1}{2}mv^2$$$$T.E=K.E+P.E= \dfrac{1}{2}mv^2 + (-\dfrac{GMm}{r})$$But $$v^2= \dfrac{GM}{r}$$$$T.E= \dfrac{1}{2}mv^2+ (-mv^2)$$$$\implies T.E= -\dfrac{1}{2}mv^2$$Physics

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