Question

# A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :

A
2mgR
B
mgR2
C
2mgR3
D
mgR3

Solution

## The correct option is D $$\displaystyle -mg\frac { R }{ 3 }$$Gravitational potential energy at distance $$r$$ from the center of the earth is given as,$$P = -\dfrac{GM_E m}{r} = -\dfrac{GM_E m}{3R} = -\dfrac{GM_E m(R/3)}{R^2}$$$$\implies P = -mg\dfrac{R}{3}$$Option D is correct.Physics

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