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Question

A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :


A
2mgR
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B
mgR2
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C
2mgR3
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D
mgR3
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Solution

The correct option is D $$\displaystyle -mg\frac { R }{ 3 } $$
Gravitational potential energy at distance $$r$$ from the center of the earth is given as,
$$P = -\dfrac{GM_E m}{r} = -\dfrac{GM_E m}{3R} = -\dfrac{GM_E m(R/3)}{R^2}$$
$$\implies P = -mg\dfrac{R}{3}$$
Option D is correct.

Physics

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