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Standard XII

Chemistry

Internal Energy

A sealed cont...

Question

A sealed container with negligible coefficient of volumetric expansion contains helium (a mono-atomic gas). When it is heated from 300 K to 600 K, the average KE of helium atoms is:

halved

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unchanged

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doubled

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increased by factor

\sqrt{2}

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Solution

The correct option is C doubled
$t h e a v a r a g e K E o f n m o l e s o f g a s a t t e m p T i s \frac{3}{2} n R T w h e n t e m p i s d o u b l e d \frac{3}{2} n R (2 T) = 2 \times \frac{3}{2} n R T s o K E d o u b l e s$

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Similar questions

Q. Helium gas is filled in a closed vessel (having negligible thermal expansion coefficient). When it is heated from 300 K to 600 K, then average kinetic energy of helium atom will be :

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A sealed container with negligible coefficient of volumetric expansion contains helium (a mono-atomic gas). When it is heated from 300 K to 600 K, the average KE of helium atoms is:

The correct option is C doubledtheavarageKEofnmolesofgasattempTis32nRTwhentempisdoubled32nR(2T)=2×32nRTsoKEdoubles

The correct option is C doubled
$t h e a v a r a g e K E o f n m o l e s o f g a s a t t e m p T i s \frac{3}{2} n R T w h e n t e m p i s d o u b l e d \frac{3}{2} n R (2 T) = 2 \times \frac{3}{2} n R T s o K E d o u b l e s$