A series in G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying odd places, then the common ratio will be equal to
The correct option is
Let there be 2n terms in the given G.P. with first term a and the common ratio r.
In this case the first term which is at odd place will remain a but the common ratio will become r2 because the next term of the sequence will be at third position i.e. ar2
So, now according to the question
Then, a r2n−1(r−1) = 5a (r2n−1)(r2−1)