A shop has 30 red and 45 blue bangles- nbsp-If Siya buys 4-5 of the red and 1-9 of the blue bangles- how many bangles does she buy in all- 19-23-29-26-

The correct option is C 29 Number of Red Bangles = 30 4/5 of red bangles = 4/5̸1×3̸0̸^6 = 24 Number of Blue bangles = 45 1/9 of blue bangles = 1/9̸1×4̸5̸^5=5 ...

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Byju's Answer

Standard V

Mathematics

Multiplication of Fractions

A shop has 30...

Question

A shop has 30 red and 45 blue bangles. If Siya buys $\frac{4}{5}$ of the red and $\frac{1}{9}$ of the blue bangles, how many bangles does she buy in all?

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Solution

The correct option is C
29

Number of Red Bangles = 30
$\frac{4}{5}$ of red bangles = $\frac{4}{/ 51} \times / 30^{6} = 24$

Number of Blue bangles = 45
$\frac{1}{9}$ of blue bangles = $\frac{1}{/ 91} \times / 45^{5} = 5$

$∴$ Total number of bangles = 24 + 5 = 29

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A shop has 30 red and 45 blue bangles. If Siya buys 45 of the red and 19 of the blue bangles, how many bangles does she buy in all?

The correct option is C 29 Number of Red Bangles = 30 45 of red bangles = 4/51×/306=24 Number of Blue bangles = 45 19 of blue bangles = 1/91×/455=5 ∴ Total number of bangles = 24 + 5 = 29

A shop has 30 red and 45 blue bangles. If Siya buys $\frac{4}{5}$ of the red and $\frac{1}{9}$ of the blue bangles, how many bangles does she buy in all?

The correct option is C
29

Number of Red Bangles = 30
$\frac{4}{5}$ of red bangles = $\frac{4}{/ 51} \times / 30^{6} = 24$

Number of Blue bangles = 45
$\frac{1}{9}$ of blue bangles = $\frac{1}{/ 91} \times / 45^{5} = 5$

$∴$ Total number of bangles = 24 + 5 = 29