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Question

A short bar magnet of moment 4 Am2 is placed in the magnetic merdian with its south-pole pointing geographic north. The distance between two null points is found to be 20 cm.

(ii)If the magnet is turned through 90 , the resultant field at the location of the null point will be.

A
25×104 T
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B
45×104 T
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C
35×104 T
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D
85×104 T
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Solution

The correct option is B 45×104 T

BR=B2H+B2eq=B2H+(Bax2)2

BR=B2H+(BH2)2=BH1+14

BR=52BH

Substituting the value gives,

BR=52×8×104=45×104 T

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