Question

A short electric dipole has a dipole moment of $16\times {10}^{-9}\text{C m}$. The electric potential due to the dipole at a point at a distance of $0.6\text{m}$ from the centre of the dipole, situated on equatorial line is
$(\frac{1}{4\pi {ϵ}_0}=9\times {10}^9{\text{Nm}}^2{\text{/C}}^2)$

• A. $200\text{V}$
• B. $400\text{V}$
• C. Zero
• D. $50\text{V}$

Answer 1

The correct option is C Zero

For an electric dipole, the potential at equatorial line is zero $i.e.$ $V_{\text{equatorial line}}=$ Zero