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Question

A Silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of Silver. Compute the ratio of the number of atoms of Gold and Silver in the ornament.


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Solution

Step 1: Finding the number of atoms of Gold and Silver:

As, Mass of Silver = mg

And mass of Gold = m100g

Because, Numberofatoms=MassAtomicmass×NA

So, NumberofatomsofSilver=(m108)×NA

and NumberofatomsofGold=(m(100×197))×NA.

Step 2: Finding the ratio of number of atoms of Gold to Silver:

As, the ratio of number of atoms from Gold to Silver would be = Au:Ag

So, the ratio = m(100×197)×NA:m108×NA

Ratio would be: 108:100×197

Therefore, the ratio of number of atoms of Gold to Silver is : 1:182.41


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