1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y=kt2, where y is the vertical displacement and k=1 msâˆ’2. The time period now becomes T2. The ratio T21T22 is equal to (g=10 msâˆ’2)

A
65
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
56
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
1
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
45
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is A 65The point of suspension is moved up according to the relation : y=kt2 This implies that the simple pendulum is in an accelerated frame moving up with acceleration. ay=d2ydt2=2k ay=2 ms−2 (∵ k=1 ms−2) We know that, T1=2π√lg and T2=2π√lgeff=2π√lg+ay ∴T21T22=g+ayg=10+210=65

Suggest Corrections
41
Join BYJU'S Learning Program
Join BYJU'S Learning Program