A simple pendulum of frequency n is taken up to a certain height above the ground and then dropped along with its support so that it falls freely under gravity. The frequency of oscillations of the falling pendulum will

Remain equal to n

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Become greater than n

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Become less than n

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Become zero

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Solution

The correct option is D Become zero
The frequency of a pendulum is given by n = $\frac{1}{2 π} \sqrt{\frac{g}{l}}$ Where g is the acceleration due to gravity. A pendulum falling freely is weightless, i.e., the effective gravity is zero. Therefore, its frequency becomes zero and it stops oscillating. Hence the correct choice is (d)

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Similar questions

Answer the following questions:

(a) Time period of a particle in SHM depends on the force constant k and mass m of the particle:

. A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?

(b) The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than. Think of a qualitative argument to appreciate this result.

(c) A man with a wristwatch on his hand falls from the top of a tower. Does the watch give correct time during the free fall?

(d) What is the frequency of oscillation of a simple pendulum mounted in a cabinthat is freely falling under gravity?

Q. Answer the following questions : (a) Time period of a particle in SHM depends on the force constant k and mass m of the particle: T = 2π √(m/k) A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum? (b) The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than 2π √( l /g) Think of a qualitative argument to appreciate this result. (c) A man with a wristwatch on his hand falls from the top of a tower. Does the watch give correct time during the free fall ? (d) What is the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity ?

Q. Answer the following questions :
(a) Time period of a particle in SHM depends on the force constant k and mass m of the particle:

T = 2 π \sqrt{\frac{m}{k}}

. A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?
(b) The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angle of oscillation a more involved analysis shows that T is greater than

2 π \sqrt{\frac{l}{g}}

. Think of a qualitative argument to appreciate this result.
(c) A man with a wristwatch on his hand falls from the top of a tower. Does the
watch give correct time during the free fall ?
(d) What is the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity ?

Q. A simple pendulum of frequency n is taken up to a certain height above the ground and then dropped along with its support so that it falls freely under gravity. The frequency of oscillations of the falling pendulum will

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