CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A simple pendulum of length of mass m and length I = 0.5 m is hanging from ceiling of car. The car is kept on a horizontal plane. The car starts accelerating on the horizontal road with acceleration of 5 m/s2. Find the time period of oscillations of the pendulum for small amplitudes about the means position.

A
1251/4 sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
253/4 sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25 sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
251/4 sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 251/4 sec

Time period of a simple pendulum in a accelerating vehicle is given by
T=2πlgeffT=2πl(g2+a2)T=2π2l(g2+a2)
Here we need to have following approximations in calculations to reach at exact solution,
π210 and g10
T=2π2l(g2+a2)=210×0.5102+52T=25102+52=2122+1=215=251/4sec


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon