A sinusoidal current has an rms value of $14 m A$ . The peak-to-peak value is

45.12 m A

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16 m A

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39.6 m A

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22.6 m A

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Solution

The correct option is C $39.6 m A$
Rms value of current $I_{r m s} = 14 m A$
Peak value of current $I_{o} = \sqrt{2} I_{r m s}$
$∴$ $I_{o} = \sqrt{2} \times 14 = 19.8 m A$
Thus peak-to-peak current $I_{p p} = 2 I_{o}$
$⟹$ $I_{p p} = 2 \times 19.8 = 39.6 m A$

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