A skydiver who weighs 60 kg is moving at terminal speed. He covers 40 m in 2 seconds. The rate of doing work by the sky diver is ___ .

Open in App

Solution

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = Force x Displacement
$= (60 \times 10 \times 40) J$
So, power spent in 2 seconds $= (60 \times 10 \times \frac{40}{2}) W$

$= 12000 W$

$= 12 K W$

Suggest Corrections

Similar questions

A skydiver who weighs 60 kg is falling down at a certain speed. He covers 40 m in 2 seconds. The rate of doing work by the skydiver is [Take $g = 10 m / s^{2}$ ]

A 60 kg skydiver moving at terminal speed 40 m in 2 seconds. The sky diver is spending a power of

___ KW.

A 60 kg skydiver moving at terminal speed covers 40 m in 2 seconds. The skydiver is spending a power of

___ KW.

A skydiver who weighs 60 kg is falling down at a certain speed. He covers 40 m in 2 seconds. The rate of doing work by the skydiver is [Take $g = 10 m / s^{2}$ ]

Q. A skydiver with mass of

60 k g

is moving at a terminal speed of

40 m

2 s e c o n d s

. Rate of work done by gravity is _____. Take

g = 10 m s^{- 2}

Join BYJU'S Learning Program

A skydiver who weighs 60 kg is moving at terminal speed. He covers 40 m in 2 seconds. The rate of doing work by the sky diver is ___ .

Power spent by the skydiver = work donetime Work done in 2 seconds = Force x Displacement =(60×10×40) J So, power spent in 2 seconds =(60×10×402) W =12000 W =12 KW

Power spent by the skydiver = $\frac{w o r k d o n e}{t i m e}$

Work done in 2 seconds = Force x Displacement
$= (60 \times 10 \times 40) J$
So, power spent in 2 seconds $= (60 \times 10 \times \frac{40}{2}) W$

$= 12000 W$

$= 12 K W$